Integrand size = 24, antiderivative size = 24 \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\text {Int}\left (\frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2},x\right ) \]
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Not integrable
Time = 0.01 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx \\ \end{align*}
Not integrable
Time = 0.90 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx \]
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Not integrable
Time = 0.05 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00
\[\int \frac {\left (b \,x^{4}+c \,x^{2}+a \right )^{p}}{e \,x^{2}+c}d x\]
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Not integrable
Time = 0.27 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\int { \frac {{\left (b x^{4} + c x^{2} + a\right )}^{p}}{e x^{2} + c} \,d x } \]
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Timed out. \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\text {Timed out} \]
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Not integrable
Time = 0.22 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\int { \frac {{\left (b x^{4} + c x^{2} + a\right )}^{p}}{e x^{2} + c} \,d x } \]
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Not integrable
Time = 0.30 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\int { \frac {{\left (b x^{4} + c x^{2} + a\right )}^{p}}{e x^{2} + c} \,d x } \]
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Not integrable
Time = 7.81 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {\left (a+c x^2+b x^4\right )^p}{c+e x^2} \, dx=\int \frac {{\left (b\,x^4+c\,x^2+a\right )}^p}{e\,x^2+c} \,d x \]
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